3x+2-4x^2=0

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Solution for 3x+2-4x^2=0 equation: 



3x+2-4x^2=0

a = -4; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-4)·2
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{41}}{2*-4}=\frac{-3-\sqrt{41}}{-8}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{41}}{2*-4}=\frac{-3+\sqrt{41}}{-8}
$

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